Jawapan

2016-02-13T10:46:21+08:00
2x + 3y + 1 = 0
y =  \frac{-2x - 1}{3}

x² + 6xy + 5 = 0
x² + 6x( \frac{-2x - 1}{3} ) + 5 = 0
x² - 4x² - 2x + 5 = 0
-3x² - 2x + 5 = 0
(x - 1)(3x + 5) = 0

x = 1
x =  \frac{-5}{3}

*pastu masukkan nilai y