Jawapan

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2016-02-23T01:20:24+08:00
T1 = 985 = a
T2 = 955
T3 = 925

d = T2 - T1
d = 955 - 985
d = -30

tinggi = 15 cm
bilangan blok yang diperlukan
= 300/15
= 20

ai) panjang blok paling atas, T20

= a + 19d
= 985 + 19(-30)
= 985 - 570
= 415 cm

ii) jumlah panjang blok2 itu, S20

= 10 (2a + 19d)
= 10 [2(985) + 19(-30)]
= 14000 cm

b) tinggi maksimum tangga itu

Tn > 0
a + (n-1)d > 0
985 +(n-1)(-30) > 0
(-30)(n-1) > -985
n - 1 < (-985) bahagi (-30)
n - 1 < 32.8
n < 33.8

Nilai maksimum, n = 33
1 5 1