Jawapan

  • Pengguna Brainly
2016-03-12T13:40:55+08:00
2x+3y^2=4 2x = 4 - 3y^2 x = 2 - 3/2 y^2 2x^2-y=1 2(2-3/2 y^2) - y = 1 4 - 3y^2 - y - 1 = 0 3y^2 + y + 1 - 4 = 0 3y^2 + y - 3 = 0 y = 0.8471 , y = - 1.180 x = 2 - 3/2(0.8471)^2 x = 0.9236 x = 2 - 3/2(-1.180)^2 x = 4.089
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