Solve the following :

a) The width of a rectangle is half of its length.If the perimeter of the rectangle is 21 cm, what is its length?

b) Given that ( 13x + 7 ) and ( 20 + 26x ) have the same value,find the value of x.

c) The total value of some 20 cents and 50 cents coins is RM 168.The number of 20 cents coins is five times the number of 50 cents coins.Find the numbers of 20 cents and 50 cents coins.

2

Jawapan

Jawapan Paling Bijak!
2016-06-11T15:00:52+08:00
1)alphabet a for the lenght
a+a+[1/2×(a+a)]=21
2a+(1/2×2a)=21
2a+a=21
3a=21
a=21÷3
=7

1 5 1
2016-06-11T15:01:23+08:00
 a) x=3.5cm, its length is 7cm (3.5 times 2)
b) 13x + 7 = 20 + 26x
7-20 = 26x-13x
-13 = 13x
x= -1
c) x sebagai berapa banyak/anon
20 cent jadi 5 x sbb dia kata 20 cents 5 kali bil 50 cents
50x + 20 (5x) = 16800 (senang kalau tukar terus dlm cent)
x = 112
20 cents = 112 x 5 x 20
50 cents = 112 x 50
 the numbers of 20 cents coins - 560
the numbers of 50 cents coins - 112
1 5 1
b) it stated that the value is the same, so awk compare
tq ^-^
saya dah edit jwpn :)
ok..tq sy dh faham:)
yg c tu sy kurang faham..hehe