Jawapan

2014-07-09T17:13:56+08:00
Factor out the common term 5
5(u2−16)
u2−16 fits the form a2b2
Rewrite it where a=u and b=4
(u)2(4)2
Apply this rule: a2b2=(a+b)(a−b)
Answer=5(u+4)(u−4)
1 3 1
2014-07-09T17:25:20+08:00
5u² - 80
= 5(u² - 16)
= 5(u + 4)(u - 4)
1 3 1