# How to solve (3x)^3 x (9x)^-1= (x^3)^1/2

1
dari Shurendran
Whatsapp akak ni 0172847059 dia buat tuisyen math online
Ok terima kasih
Shuren....knp awak block cikgu tu
Cikgu tu baru je nak ajar awak
Oh tersilap
Phone saya Ada masalah
Ok saya add Balik

## Jawapan

2016-09-19T20:20:59+08:00
(3x)^3 X (9x)^-1= (x^3)^1/2...... 3^3 x^3 X 9^-1 x^-1 =x^3/2..... 3^3 x^3 X 3^2-1 x^-1=x^3/2...... 3^(3+2-1) x^(3-1) = x^3/2...... 3^4 x^2 = x^3/2..... 81 x^2 =x^3/2.... 81 = x^3/2 bahagi x^2..... 81 = x^(3/2 - 2)...... 81 = x^-1/2..... 81 = 1 bahagi x^1/2.... 81 = 1 bahagi x^-2.... 81 = x^2.... x = punca kuasa 81..... x = +-9( jika Addmath).... x = 9(bagi math biasa)...
Jawapannya 1/9..betul ke?
Macm mana boleh 1/9??
Ah, btul lah... aq careless
3x)^3 X (9x)^-1= (x^3)^1/2...... 3^3 x^3 X 9^-1 x^-1 =x^3/2..... 3^3 x^3 X 3^2(-1) x^-1=x^3/2...... 3^(3-2) x^(3-1) = x^3/2...... 3 x^2 = x^3/2..... 3x^2 =x^3/2.... 3= x^3/2 bahagi x^2..... 3 = x^(3/2 - 2)...... 3 = x^-1/2..... 3 = 1 bahagi x^1/2.... 3 = 1 bahagi x^-2.... 3 = x^2.... x = punca kuasa 3 ....