Jawapan

  • ben2
  • Pengguna Baru
2016-09-24T02:10:15+08:00
If it is a rhombus,the diagonals of it always intersect each other at right angle
so let find pr equation first
using formula m=y2-y1/x2-x1
then substitute it in linear equation general formula
y-y1=m(x-x1)
y=3/2 x-7/2,
as we know pr is perpendicular to qs
the gradient m will convert into -2/3
m1m2=-1
m2(3/2)=-1, m=-2/3
let find the point of intersection,
the midpoint of the pr line
(x,y)=( (5+1)/2 , (4-2)/2 )
(3,1)
from this coordinate it perpendicular to another qs diagonal.
equation of qs is y-1 = -2/3(x-3)
***y= -2/3 x +3 or 3y=-2x+9