# If Kamil gave Kuhan RM15, they would then have the same amount. But if Kuhan gave Kamil RM25, Kamil would have twice as much as Kuhan left. How much does each of them actually have?

2
dari douglasting123

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2016-09-22T17:16:32+08:00
Kamil:30
K-k=30-15=15

kamil:15 kuhan:15

kamil:25+15=40 kuhan:20

kamil: 30 kuhan:45
sorry kalau salah
i just try my best
2016-09-22T19:24:36+08:00
You can solve the question using simultaneous equation.
Kamil gave Kuhan RM15 : a - 15
They have the same amount of money : (a + b)/2
Equation 1 : a - 15 = (a + b)/2

Kuhan gave Kamil RM25 : b - 25
Kamil have as much as Kuhan left : 2(2b - 25) <-- Kamil's money
Equation 2 : b - 25 = (a + b) - 2(2b - 25)
(a + b) - 2(2b - 25) is Kuhan's money.

Equation 1 : Express a in terms of b.
2a - 30 = a + b
a = 30 + b

Substitute it into Equation 2.
b - 25 = (30 +b + b) - 2(b - 25)
b = RM 105

a = 30 + 105
a = RM 135

For life's sake, lets prove the values are correct.

Kamil gave RM15 and then they have the same amount of money.
135 - 15 = RM 120
Total money : 105 +135 = RM 240
Then, 120 + 120 should be RM 240
120 + 120 = RM 240
Proven!

Next.
Kuhan gave RM 25 and Kamil have twice as much as Kuhan left.
105 - 25 = RM 80 <-- Kuhan's money
Kamil's money is 2(Kuhan's money)
Kuhan's money + 2(Kuhan's money) should be RM 240.
80 + 2(80) = RM 240
Proven!
Yay :D
I am wondering if this answer is correct, can anyone confirm it?