Jawapan

2015-03-30T11:26:01+08:00
X + y = 6
      y = 6 - x
 \frac{2}{x} + \frac{5}{y} =3 \\ \frac{2}{x} + \frac{5}{6-x} =3  \\ x(6-x)\frac{2}{x} +x(6-x)\frac{5}{6-x}=x(6-x)3 \\ 12-2x+5x=18x-3 x^{2}  \\ 3 x^{2} -18x-2x+5x+12=0 \\ 3 x^{2} -15x+12=0 \\  x^{2} -5x+4=0 \\ (x-4)(x-1)=0 \\  x_{1} =4 \\ x_{2} =1
1 5 1