Harga 3 biji mangkuk dan 2 biji gelas ialah rm9. diberi bahawa harga sebiji mangkuk adalah 50 sen lebih mahal daripada harga sebiji gelas. cari harga 2 biji mangkuk dan 3 biji gelas. menggunakan persamaan serentak.

2

Jawapan

Jawapan Paling Bijak!
  • gash
  • Tangan Bantuan
2015-09-29T15:35:24+08:00
Lets say, mangkuk = x
              glass       = y
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3x + 2y = RM 9 (1)
x - RM 0.5  = y         (2)

3(x - y = 0.5) 
3x -3y = 1.5    (3)

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using elimination method..........

(1) - (3)
3x -3x +2y +3y = RM9 - RM1.5
5y                     = RM 7.5
y                       = RM 1.5

y= RM 1.5 into (3)
    3x -3 ( RM 1.50) =RM 1.5
    3x - RM 4.5        = RM 1.5
    3x                       = RM 1.5 + RM 4.5
    x                         = RM6 divide 3
    x                         = RM 2
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x = RM 2
y = RM 1.5

2x = RM 4
3y = RM 4.5

2x+3y = RM 8.50 #
1 5 1
2015-09-29T17:16:27+08:00
Gantikan m = g + 0.5 ke dalam persamaan

3m + 2g = 9
3 (g + 0.5) + 2g  = 9
3g + 1.5 + 2g = 9
5g = 9 - 1.5
5g = 7.5
g = 7.5 /5
g = RM1.50

m = g + 0.5
m = 1.5 + 0.5
m = RM2.00

2m + 3g
= 2(2) + 3(1.5)
= 4 + 4.5
= RM8.50